Protonation States and pKa
Transcription
Protonation States and pKa
Munia Mukherjee April 16th, 2007 munia@medusa.bioc.aecom.yu.edu Protonation States and pKa Suggested Readings: • • • • • • • Markley, J. L. (1975). “Observation of Histidine Residues in Proteins by Nuclear Magnetic Resonance Spectroscopy.” Acc. Chem. Res. 8, 70-80. Cosgrove, M.S. et.al (2002), “The Catalytic Mechanism of G-6-P Dehydrogenases,…” Biochemistry, 41, 6939-6945. Bartik, K. et al. (1994), “ Measurement of the Individual pKa Values of Acidic Residues of Hen And Turkey Lysozymes by Two Dimensional 1H NMR.” Biophysical J., 66, 1180-1184 Anderson, D.E. et al. (1990). “pH induced denaturation of proteins: A single salt bridge contributes 3-5 kCal/mol to the free energy of folding of T4 lysozyme.” Biochemistry, 29, 24032408. Smith, R. et al. (1996) “Ionization states of the catalytic residues in HIV-1 protease”. Nat. Struct. Biol., 3, 946-950. Dyson, H.J. et al. (1996) “Direct Measurement of the Aspartic Acid 26 pKa for reduced E.coli Thioredoxin by 13C NMR” Biochemistry, 35, 1-6 Pujato, M. (2006), “The pH-dependence of amide chemical shift of Asp/Glu reflects its pKa in intrinsically disordered proteins with only local interactions” Biochimica Biophysica Acta, 12271233 Deprotonation reaction: HA + H2O A- + H 3 O+ Ka = [A-] [H3O+] (1) [HA] Henderson-Hasselbach equation: 1 1 [A-] [H3O+] = Ka [HA] -log [H 3O+] = -log Ka + log [A-] / [HA] (2) (3) pH = pKa + log 1- θ (4) θ θ is degree of protonation or occupancy: Number of bound protons as a function of pH The pKa of a titrating site is defined as the pH for which the site is 50% occupied: The pH for which the occupancy θ is 0.5. Definition of pKa pH = pKa + log 1- θ θ θ (pH ) = 1 1 + e −ln10(pKa −pH ) Titration curve One state transition pK a = 4.0 Titration curves of amino acids Since amino acids are (at least) diprotic their titration curves appear a little different from a simple acid -each proton will have a pKa value and thus there are two or more stages in the titration curve Depending on where in the titration you are looking (i.e. at which pH) a different form of the amino acid will be prevalent Remember that pH is notation for proton concentration and that pKa is the equilibrium constant for ionization - thus pKa is a measure of the tendency for a group to give up a proton -as the pKa increases by one unit the tendency to give up the proton decreases tenfold The positively charged amino group attached to the acarbon helps to push the departing proton of the carboxyl group out more easily. The inflection point pI is the point when removal of the first proton is complete and he second has just begun so the amino acid’s prevalent form is as a dipolar ion pH < pI: net positive charge pH > pI: net negative charge pKa of ionizable side chains pKa = pH for 50% dissociation, Note range pKa of some amino acids Factors that affect pKa values Ionizable residues encounter two differences inside folded proteins compared to water They are partly desolvated by the protein This is especially unfavorable for the charged form (because it’s an ion) but it’s also unfavorable for the neutral form (because it’s a dipole. They form new interactions with other residue. These new interactions may be energetically favorable or unfavorable. Usually the charged form is more affected than the neutral form due to these interactions e.g. an aspartate with a low pKa this aspartate is partly buried but it accepts ~4 hydrogen bonds from nearby residues it’s also close to some positively charged residues the charged form is very happy here, so it becomes more difficult to add a proton to it so we have to increase [H+] (lower pH) to add the proton so the pKa of the residue decreases from 4 to ~2 e.g. a glutamate with a high pKa this glutamate is partly buried & forms no favorable interactions with other residues this is very unfavorable for the charged form (compared with being in water) this shifts the equilibrium in favor of the neutral form so it will be protonated even at low [H+] (i.e. high pH) or does not want to be deprotonated so the pKa of the residue increases from 4.4 to ~6 Simple rules for guessing pKa shifts remember: a pKa is just the ∆G for deprotonation acidic residues (asp & glu) COOH ↔ COO– + H3O+ if charged form is unhappy: deprotonation is more difficult so pKa shifts up if charged form is happy: deprotonation is easier so pKa shifts down basic residues (arg, lys & his) NH3+ ↔ NH2 + H3O+ if charged form is unhappy: deprotonation is easier so pKa shifts down if charged form is happy: deprotonation is more difficult so pKa shifts up Reasons for interest in pKas [1] enzyme activity is pH dependent many catalytic steps involve addition or removal of protons the rates of these steps will depend on the pH and the pKas of the residues involved enzymes have optimal pHs (sometimes loss of activity at non-optimal pHs is due to unfolding of the enzyme) (Pace et al. Biochemistry 2: 2564 (1990) Reasons for interest in pKas [2] protein stability is pH dependent if the pKa of a residue is different in the folded state from its value in the unfolded state, the protein’s stability will depend on pH ∆G unfold – pH For most proteins the folded state is only 1-5 kCal/mol more favored than the unfolded state. A typical ionic interaction is around 2-5 kCal/mol. So a single ionic interaction can determine whether or not a protein will fold. Reasons for interest in pKas [3] a protonation equilibrium can be thought of as a very simple ligand-binding reaction (with the ligand being H+) knowing the pKa of a protein residue and the protein’s structure... we can start to determine the relative importance of different factors, e.g.: 1. desolvation effects 2. charge-charge interactions 3. protein dielectric properties From the change in pKa, one can determine the free energy (∆G) associated with the reaction: The standard free energy of dissociation (HA ↔ H+ + A-) is given by: ∆G° = -RT ln([H+] [A-]/[HA]) = -RT ln Ka = 2.303 RT pKa (standard state) -------(1) Actual free energy of ionization: ∆Gioniz= ∆G° + RT ln ([H+] [A-] / [HA]) ----(2) Suppose the ionization reaction is coupled to some other interaction: e.g. binding of a proton to A - changes the interaction of A- with some other group in the molecule. ∆Gtotal = ∆Gioniz + ∆Ginter = ∆G° + ∆Ginter + RT ln ([H+] [A-] / [HA]) ------(3) At equillibrium ∆Gtotal = 0. The H+ concentration at which the acid is half ionized is: (H+)1/2 = e -(∆G° + ∆Ginter )/RT -----------(4) The apparent pKa’ is: pKa’ = -log (H+)1/2 = (∆G° + ∆Ginter ) / 2.303 RT ---------(5) For a model system without coupling: pKa = ∆G° / 2.303 RT ----------(6) Therefore, from the difference in the two pKa values, the interaction energy can be calculated as ∆Ginter = 2.303 RT (pKa’ – pKa) --------------(7) pKa analysis by NMR The side chain 1H, 13C or 15N chemical shift changes with ionization. Usually the largest change occurs closest to the site of protonation / deprotonation. Monitor the chemical shift change as a function of pH. Fit to modified Hill Equation: δHA + δA- x 10pH-pKa δobs = δHA is the chemical shift in the acidic pH limit δA- is the chemical shift in the basic pH limit 1+ 10pH-pKa 8.0-8.8 ppm 2 4 Ionization of Histidine 6.8-7.2 ppm 1 C2H proton appears at higher frequency than most other protons and is sensitive to the protonation of the ring. 3 C2HC4H H +H3 N C COO- H C H + 4 C H N 1 C C2 CαH CβH 0 10 H Raise pH N3 H H ppm 10 0 Titration of the C2H of Histidine 1 Shift measured with multiple 1D spectra starting with pH 1.0 and moving through to pH 9. The chemical shift change of the proton on C2 reflects the protonation state of N1 50% of complete change Chemical Shift Change ∆δ (ppm) pKa = 5.2 0 1 3 5 7 9 11pH Observation of Histidine Residues in Proteins by Means of Nuclear Magnetic Resonance Spectroscopy. (Markley J., Acc Chem Res. 8, 1975, 70-80) 4 histidines which could be monitored and have their pKa’s measured. Chemical shift change of C2H and C4H monitored as a function of pH using 1D NMR H1 = His105 H2 = His119 H3 = His12 H4 = His48 C2H titration Measure pKa of each histidine pKa C4H titration His105 6.7 His119 6.2 His12 5.8 His48 is more complex, sudden discontinuity in the curve. There is a conformational change affecting this peak so that at some pHs two peaks were observed. H4a and H4b were acid and base stable forms. Found that 200mM Na+CH3COOhelped to stabilize the protein. Can then determine that the pKa of C2H is 6.31. Repeat titrations in the presence of an inhibitor. His105 in this case, cytidine-3’monophosphate (3’-CMP) His48 O N O OPO3 - His12 His119 HOCH2 NH2 OH His48 and His105 are unchanged His12 and His119 curved are shifted downfield. His119 changes from 6.2 to 8.0 His 12 changes from 5.8 to 7.4 Why downfield?? Both His12 and His119 are protonated in the enzymeinhibitor complex. The proton is protected from exchange by the presence of the inhibitor. Need to go to higher pH to remove it. NH2 HOCH 2 O N O OPO3 - OH pKa values of acidic residues of hen and turkey lysozymes by two dimensional 1H NMR (Bartik, K. et.al. Biophys J., 66, 1994, 1180-1184) pH= 1.1 pH= 5.9 Both enzymes have identical activity profile as a function of pH as indicated by identical pKa values of the residues in the active site. 2D DQFCOSY Protein is positively charged (pI = 11) between pH 1 to pH 7 (titration range). This results in an overall decrease in the stability of the positively charged histidine residues and increase in the stability of the negatively charged Asp and Glu residues. Therefore, a decrease in the pKa values is observed for these residues from their standard values. pKa values of the conserved residues at the active site (Glu35 and Asp52) is higher than rest of the residues due to the hydrophobic nature of the active site cleft and interaction between Glu 35 and Asp52. Direct Measurement of the Aspartic Acid 26 pKa for Reduced E. Coli Thioredoxin by 13C NMR (J. Dyson et al., Biochemistry, 35, 1996, 1-6.) pH O H H C—C—N—C—CH H—C—H C O O- Two dimensional HCACO spectrum of thioredoxin at pH 8.52. pKa determined using modified 2D HCACO experiment that detects coupling between 13CO of a carboxyl group and the adjacent 13CβH or 13CγH. O H H C—C—N—C—CH H—C—H C O O- The carboxyl group of Asp 26 is buried in a hydrophobic environment that elevates its pKa value to 7.3-7.5 from a standard value of 4.0. Ionization of Asp26 also affected by two Cysteine thiol groups ionizing at the active site. Plot of chemical shift as a function of pH