JUNE EXAM QUESTIONS (LIVE) 03 JUNE 2015
Transcription
JUNE EXAM QUESTIONS (LIVE) 03 JUNE 2015
JUNE EXAM QUESTIONS (LIVE) 03 JUNE 2015 Section B: Practice Questions Question 1 Multiple choice 1.1 Study the following list of molecules: (i) Sugar (ii) Phosphate (iii) Nitrogenous base (iv) Amino acid Which one of the following combinations represents components of a nucleotide? A (i), (ii) and (iv) only B (i), (ii) and (iii) only C (i), (ii), (iii) and (iv) D (ii), (iii) and (iv) only Questions 1.2 and 1.3 refer to the diagram below the structure of the human ear 1.2 1.3 Which part sends vibrations to the ossicles? A 3 B 1 C 4 D 5 Which part maintains equal pressure on either side of the tympanic membrane? A 4 B 3 C 2 D 1 1.4 Below is a set of events following fertilisation in humans. 1. The embryo is embedded in the uterine wall in humans. 2. A zygote is formed in the Fallopian tube. 3. Cell division occurs to form a ball of several hundred cells. 4. The blastocyst remains free for several days in the uterus. Which ONE of the following represents the correct order in which the above events occur? 1.5 A. 2, 3, 4, 1 B. 2, 1, 3, 4 C. 3, 2, 4, 1 D. 1, 3, 2, 4 The list below gives some of the stages involved in gamete and zygote formation. 1. Prophase I 2. Prophase II 3. Metaphase I 4. Fertilisation Which ONE of the following combinations of the above stages contributes to genetic variation? 1.6 A. 1, 2 and 3 B. 1, 3 and 4 C. 2 and 3 D. 3 and 4 In analysing the number of different bases in a DNA sample, the following result would be consistent with the base-pairing rules: A. A=G B. A+G=C+T C. A+T=G+C D. A=C Question 2 The diagram shows part of a DNA molecule in the process of replication. C G P G C A T Q T R G C G C G G C C 2.1. 2.2. S Label the following on the diagram: 2.1.1. a sugar molecule 2.1.2. a phosphate group Describe exactly where DNA is found in a humancell? (2) A portion of DNA at the beginning of a gene has the nucleotide sequence: TACATAGCGTAT 2.3 What is the mRNA sequence produced on this template? (3) 2.4. Use the table below to determine the amino acids bonded together using this mRNA template. (4) Question 3 In pea plants the allele for round seeds (R) is dominant over the allele for wrinkled seeds (r). Theallele for yellow seeds (Y) is dominant over the allelefor green seeds (y). Plant A, heterozygous for both seed shape and seed colour, was crossed with plant B, which had wrinkled, green seeds. 3.1 Write down the genotype of: (a) Plant A (b) Plant B (2) 3.2 Write down ALL the possible genotypes of the gametes of plant A. 3.3 State the phenotype of an offspring having the genotype: 3.4 (a) rrYy (b) RrYy (2) (2) When plant B was crossed with plant C, all the offspring had round yellow seeds. Use this information and write down the genotype of plant C. (2) Question 4 The inheritance of fur colour in cats is sex-linked. The tortoise-shell colour of cats is a combination of B black and orange fur. The allele for black fur is represented by X and the allele for orange fur is O represented by X . A female cat with a tortoise-shell colour mates with an orange male cat. HINT: The sex chromosomes/gonosomes in cats are the same as in humans. 4.1 B O Use the symbols X , X and Y to represent a genetic cross of the mating stated above. Also indicate the proportion of the F1 phenotypes. (7) 4.2 Explain why the male kittens can never have the tortoise-shell colour. (2) 4.3 Explain why the female kittens can have the tortoise-shell colour. (2) Question 5 The diagram below represents a cross-section of a human seminiferous tubule in which a process is occurring. 5.1 Name the specific process illustrated in the seminiferous tubule which leads to the formation of structure A. (1) 5.2 Name the hormone produced by the organ containing seminiferous tubules. (1) 5.3 Give ONE function of the hormone named in QUESTION 5.2 (1) 5.4 How many chromosomes are there in each: 5.5 (a) Spermatogonium cell (b) Spermatid Make a labelled drawing to show the structure of the cell labelled A. (2) (5) Question 6 Start with a cell containing FOUR chromosomes and describe ALL the chromosomal changes that occur during meiosis, resulting in the formation of abnormal gametes due to non-disjunction in meiosis 1. Question 7 The diagram below shows a part of the central nervous system. 7.1 Give labels for each of the following: (a) C (b) Microscopic gap D (c) E (d) F (e) G 7.2 Explain ONE consequence for the body if A is damaged. (1) 7.3 Give TWO examples of reflex actions. (2) 7.4 Draw a labelled diagram of neuron B to show its structure. (5) Question 8 The diagram shows two eyes (X and Y) focused on objects (represented by arrows) at different distances from the eye. Objects A and C were 2 metres away from the eye. Objects B and D were 7 metres away from the eye. 8.1 8.2 Write down the LETTER ONLY of the object that: (a) Eye X is focused on (b) Eye Y is focused on Name and describe the process that allows eye Y to form a clear image on the retina. Section C: Solutions Question 1 1. 2. 3. 4. 5. 6. B D A A B C (2) (5) Question 2 2.1. 2.2. 2.3. 2.4. forming chromosomes in nucleus , in mitochondria AUG UAU CGC AUA meth tyr arg isoleu Question 3 3.1 3.2 3.3 3.4 (a) RrYy (b) rryy RY, Ry, rY, ry (a) wrinkled, yellow seed (b) Round, yellow seed RRYY (4) (2) (3) (4) Question 4 4.1 4.2 The allele for the trait is carried on the X-chromosomeonly/ Y-chromosome does not carry the allele for the trait the trait only shows when it is in the heterozygouscondition 4.3 Both alleles are dominant/co-dominant - Both colours are equally expressed in the phenotype Question 5 5.1 Spermatogenesis 5.2 Testosterone 5.3 Stimulates the development of primary male sex organsStimulates the development of secondary male characteristics Stimulates development of sperm 5.4 (a) 46 chromosome (b) 23 chromosome 5.5 Question 6 Each chromosome shortens and becomes visible as two chromatids joined by a centromere Homologous chromosomes come to lie next to each other Chromatids from each homologous chromosome overlap/crossing over occurs The point of overlap is called the chiasma Genetic material is exchanged between the homologous chromosomes The chromosomes line up along the equator in homologous pairs attached to the spindle fibres When the spindle fibres shorten/contract o All 4 chromosomes are pulled to one pole due to non-disjunction Resulting in two cells o one with 4 chromosomes, o and one with no chromosomes. The cell with 4 chromosomes undergoes meiosis 2 The 4 chromosomes line up at the equator in a single row When the spindle fibres shorten/contract the centromeres split and chromatids/daughter chromosomes are pulled to the opposite poles of the cell Two cells result o Each with a nucleus containing 4 chromosomes o Resulting in diploid gametes Any 4 compulsory* points + any other 13 Question 7 7.1 (a) C - Effector/muscle (b) D - Synapse (c) E - Spinal cord (d) F - Connector neuron/interneuron (e) G - Dorsal root/spinal nerve 7.2 Impulse will not reach the CNS/the body will be unaware of the stimulus and no reflex action will occur, causing harm to the body Any (2) 7.3 Pulling your hand away from a hot objectblinking/coughing/ sneezing//knee-jerk/ any appropriate stimulus and response/ (swallowing/peristalsis/breathing/heartbeat/dilation and constriction of blood vessel/pupillary mechanism/ yawning/salivation) (Mark first TWO only) Any 7.4 Question 8 8.1 8.2 (a) B (b) C Accommodation (1) − Ciliary muscles contract − Suspensory ligaments slacken − Tension on lens decreases − Lens becomes more convex − Refractive power of lens increases − A clear image now forms on the retina